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(values are 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E, or F)
you are quoting a heck of a lot there.
[QUOTE]blah blah blah[/QUOTE] to reply to ShadowSD.
Please remove excess text as not to re-post tons
message
[QUOTE="ShadowSD:450053"]SacreligionNLI said:[QUOTE]my sister says that when you get to larger sets that neither k or 1 could be picked[/QUOTE] Neither k nor 1 have to be picked for this to work, that's the whole point. In the second example above where k=3, I neglected to mention (2,4,5,6) as a possible chosen set; that right there is a set of numbers without k or 1, but in which you can find at least one pair where one can be x and one can be y. Even if you have neither k or 1, you can't avoid picking two numbers where one is the multiple of the other - and that's the heart of the proof being requested. Numbers increase at a constant rate, so no matter how big the set gets, these relationships never change; it's all relative. [/QUOTE]
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